If A:B=3:4 and B:C=12:13 find A:C.
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In given figure ABC is a triangle in which AB = AC and D is a point on AC such that BC^2 = AC × CD . Prove that BD = BC.
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ABC is a triangle right angled at C.A. line through the midpoint M of hypotenuse and parallel to BC intersects AC at D. show that(i) D is the midpoint of AC(II) MD
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Geometry 2
ABC is an isosceles triangle such that AB = AC and B = 35 . AD is the median to the base BC. Then BAD is :
∆ABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also find the length of AD
∆ABC is an isosceles triangle with AB = AC = 13cm. The length of altitude from A on BC is 5cm. Find BC. - Sarthaks eConnect | Largest Online Education Community
geometry - In $\Delta ABC, AB = 13, AC = 5, BC = 12.$ Points $M,N$ lie on $ AC,BC$ respectively with $CM = CN = 4$. - Mathematics Stack Exchange
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O is the centre of an equilateral triangle ABC . F1,F2 and F3 are three forces acting along the sides AB,BC and CA as shown in the figure. What should be the
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D, E, and F are, respectively the mid - points of sides BC, CA and AB of an equilateral triangle ABC. Prove that DEF is also an equilateral triangle.
ABC is a right triangle such that AB=AC and bisector of angle C intersects the side AB at D. prove that AC+AD=BC.
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Ex 8.2, 7 - ABC is a triangle right angled at C. A line - Ex 8.2
