If A, B, C and D are angles of a quadrilateral and sin A/2 sin B/2 . sin C/2 . sin D/2 = 1/4, prove that A = B = C =
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The d.rs of two lines are given by the equations a + b + c = 0 and 2ab + 2ac - bc = 0 . Then the angle between the lines is
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![SOLVED: In triangle ABC angle A-60 degree , angle B-30 degree - angle €-90 degree AB square root of 2 Find BC and AC_ In triangle ABC AB-81,angle A-61 degree angle C-73 SOLVED: In triangle ABC angle A-60 degree , angle B-30 degree - angle €-90 degree AB square root of 2 Find BC and AC_ In triangle ABC AB-81,angle A-61 degree angle C-73](https://cdn.numerade.com/ask_images/b693107ca580498d988c411119c45cd5.jpg)
SOLVED: In triangle ABC angle A-60 degree , angle B-30 degree - angle €-90 degree AB square root of 2 Find BC and AC_ In triangle ABC AB-81,angle A-61 degree angle C-73
Let ABC be the triangle with AB = 1, AC = 3 and ∠BAC = π/2 . - Sarthaks eConnect | Largest Online Education Community
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