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In Figure 2, AD | BC. Prove that AB^2 + CD^2 = BD^2 + AC^2.
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Example 10 - ACB = 90 and CD perpendicular AB. Prove BC2/AC2
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In any triangle ABC, prove that AB^2 + AC^2 = 2(AD^2 + BD^2) , where D is the midpoint of BC.
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In the given figure, AD BC , Prove that AB^2 + CD^2 = BD^2 + AC^2
