![The following is a transition table for an NFA with states 1-5 and input alphabet a, b . There are no lambda-transitions. |l|l|l| q & delta (q, a) & delta (q, b) The following is a transition table for an NFA with states 1-5 and input alphabet a, b . There are no lambda-transitions. |l|l|l| q & delta (q, a) & delta (q, b)](https://homework.study.com/cimages/multimages/16/output5023924200238550936.png)
The following is a transition table for an NFA with states 1-5 and input alphabet a, b . There are no lambda-transitions. |l|l|l| q & delta (q, a) & delta (q, b)
![formal languages - When you convert epsilon NFA to NFA, how do you decide the final states of resultant NFA? - Computer Science Stack Exchange formal languages - When you convert epsilon NFA to NFA, how do you decide the final states of resultant NFA? - Computer Science Stack Exchange](https://i.stack.imgur.com/IbN2A.png)
formal languages - When you convert epsilon NFA to NFA, how do you decide the final states of resultant NFA? - Computer Science Stack Exchange
![formal languages - When you convert epsilon NFA to NFA, how do you decide the final states of resultant NFA? - Computer Science Stack Exchange formal languages - When you convert epsilon NFA to NFA, how do you decide the final states of resultant NFA? - Computer Science Stack Exchange](https://i.stack.imgur.com/sckZS.png)